Oracle-valeurs Listagg uniques

Je suis nouveau à L'utilisation de Listagg. Le script suivant fonctionne par rapport à lui me donne une liste de valeurs mais, la liste duplique les valeurs.

est-il possible d'utiliser Listagg pour retourner seulement une liste unique de valeurs.

j'utilise oracle 10g.

select distinct ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr, 
listagg(case when not li.paco is null then (select unique max(li1.paco) from leos_item li1 where li.av_part_no = li1.av_part_no) end, ', ') within group (order by pd.part_no) inq_no
from oes_delsegview ds, oes_address ad, oes_opos op, oes_nrbom nr, scm_prodtyp sp, leos_item li, part_description pd
where ds.delnr = ad.key
and ad.adr = ds.deladr
and ds.pos_o_status not in ('9', 'D')
and ds.pos_c_status not in ('9', 'D')
and ds.seg_o_status not in ('9', 'D')
and ds.seg_c_status not in ('9', 'D')
and ds.cunr in ('W31170','W31172')
and ds.pos_type != 'RC'
and ds.ordnr = op.ordnr
and ds.posnr = op.posnr
and ds.catnr = pd.catnr
and ds.prodtyp = pd.prodtyp
and ds.packtyp = pd.packtyp
and ds.catnr = nr.p_catnr (+)
and ds.prodtyp = nr.p_prodtyp (+)
and ds.packtyp = nr.p_packtyp (+)
and nr.c_prodtyp = sp.prodtyp (+) 
and sp.prodgrp (+) = 'COMP'
and substr(nr.c_prodtyp,1,2) not in ('MT','LF')
and nr.c_catnr = li.catnr (+)
and nr.c_prodtyp = li.prodtyp (+)
and nr.c_packtyp = li.packtyp (+)
and pd.catnr = '9780007938797'
group by ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr

le résultat de ma Listagg est:

14/061127-12, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16, 14/061127-16

ce que je voudrais voir est:

14/061127-12, 14/061127-16

Toute aide serait très apprécié.

1
demandé sur Haytem BrB 2016-02-09 20:51:14
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4 ответов

j'ai supprimé le premier distinct depuis votre déjà group by tous les champs de votre Select requête, et remplacé le case when par un select requête:

select ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr, 
    listagg((select distinct max(li1.paco) from leos_item li1 where li.av_part_no = li1.av_part_no and li.paco is not null), ', ') within group (order by pd.part_no) inq_no
    from oes_delsegview ds, oes_address ad, oes_opos op, oes_nrbom nr, scm_prodtyp sp, leos_item li, part_description pd
    where ds.delnr = ad.key
    and ad.adr = ds.deladr
    and ds.pos_o_status not in ('9', 'D')
    and ds.pos_c_status not in ('9', 'D')
    and ds.seg_o_status not in ('9', 'D')
    and ds.seg_c_status not in ('9', 'D')
    and ds.cunr in ('W31170','W31172')
    and ds.pos_type != 'RC'
    and ds.ordnr = op.ordnr
    and ds.posnr = op.posnr
    and ds.catnr = pd.catnr
    and ds.prodtyp = pd.prodtyp
    and ds.packtyp = pd.packtyp
    and ds.catnr = nr.p_catnr (+)
    and ds.prodtyp = nr.p_prodtyp (+)
    and ds.packtyp = nr.p_packtyp (+)
    and nr.c_prodtyp = sp.prodtyp (+) 
    and sp.prodgrp (+) = 'COMP'
    and substr(nr.c_prodtyp,1,2) not in ('MT','LF')
    and nr.c_catnr = li.catnr (+)
    and nr.c_prodtyp = li.prodtyp (+)
    and nr.c_packtyp = li.packtyp (+)
    and pd.catnr = '9780007938797'
    group by ds.catnr,ds.planqty, ds.ordnr, ds.posnr, ds.segnr
2
répondu Haytem BrB 2016-02-09 21:11:45
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j'ai utilisé une fonction regexp_replace pour supprimer les doublons dans ma listagg;

regexp_replace(
    listagg((select distinct max(li1.paco) from leos_item li1 where li.av_part_no = li1.av_part_no and li.paco is not null), ', ') within group (order by pd.part_no) 
    ,'([^,]+)(,)+', '') inq_no

semble fonctionner correctement.

LISTAGG dans oracle pour retourner des valeurs distinctes

0
répondu SMORF 2017-05-23 15:06:52
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vous pouvez le faire via RegEx replacement. Voici un exemple:

-- Citations Per Year - Cited Publications main query. Includes list of unique associated core project numbers, ordered by core project number.
SELECT ptc.pmid AS pmid, ptc.pmc_id, ptc.pub_title AS pubtitle, ptc.author_list AS authorlist,
  ptc.pub_date AS pubdate,
  REGEXP_REPLACE( LISTAGG ( ppcc.admin_phs_org_code || 
    TO_CHAR(ppcc.serial_num,'FM000000'), ',') WITHIN GROUP (ORDER BY ppcc.admin_phs_org_code || 
    TO_CHAR(ppcc.serial_num,'FM000000')),
    '(^|,)(.+)(,)+', '')
  AS projectNum
FROM publication_total_citations ptc
  JOIN proj_paper_citation_counts ppcc
    ON ptc.pmid = ppcc.pmid
   AND ppcc.citation_year = 2013
  JOIN user_appls ua
    ON ppcc.admin_phs_org_code = ua.admin_phs_org_code
   AND ppcc.serial_num = ua.serial_num
   AND ua.login_id = 'EVANSF'
GROUP BY ptc.pmid, ptc.pmc_id, ptc.pub_title, ptc.author_list, ptc.pub_date
ORDER BY pmid;
0
répondu DKroot 2016-04-21 03:28:36
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Super simple réponse résolu

select
regexp_replace('14/061127-12, 14/061127-16, 14/061127-16','([^,]+)(,)*(,|$)', '')


from dual

- >

14/061127-12, 14/061127-16

voir ma réponse complète ici

0
répondu ozmike 2017-05-23 15:33:15
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