Comment obtenir les coordonnées d'un élément svg?
j'utilise d3 pour tracer une ligne à partir d'une position svg relative et donc pour accéder aux coordonnées de l'élément lui-même. J'ai essayé quelque chose comme ceci (où "ceci" se réfère à l'élément)
.attr("x1", this.x)
.attr("y1", this.y)
mais les x1 et y1 par défaut à zéro. Quelle est la bonne façon d'obtenir les coordonnées de l'élément svg?
EDIT:
Voici mon code complet (sur demande). J'essaie de le mettre en œuvre sur le repliable. arbre, où je dessine une ligne quand je plane avec la souris sur un noeud de cercle. Le point de départ de la ligne doit être le cercle sur lequel je clique et le point final doit être un point fixe sur le plan svg.
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8">
<script type="text/javascript" src="d3.v3.js"></script>
<script type="text/javascript" src="d3.layout.js"></script>
<style type="text/css">
.node circle {
cursor: pointer;
fill: #fff;
stroke: steelblue;
stroke-width: 1.5px;
}
.node text {
font: 10px sans-serif;
}
path.link {
fill: none;
stroke: #ccc;
stroke-width: 1.5px;
}
</style>
</head>
<body>
<div id="chart"></div>
<script type="text/javascript">
var m = [20, 120, 20, 120],
w = 2240 - m[1] - m[3],
h = 800 - m[0] - m[2],
i = 0,
duration = 500,
root;
var tree = d3.layout.tree()
.size([h, w]);
var diagonal = d3.svg.diagonal()
.projection(function(d) { return [d.y, d.x]; });
var vis = d3.select("#chart").append("svg")
.attr("width", w + m[1] + m[3])
.attr("height", h + m[0] + m[2])
.append("g")
.attr("transform", "translate(" + m[3] + "," + m[0] + ")");
function loadData(json) {
root = json;
d3.select("#processName").html(root.text);
root.x0 = h / 2;
root.y0 = 0;
root.children.forEach(collapse);
update(root);
}
function collapse(d) {
if (d.children) {
d._children = d.children;
d._children.forEach(collapse);
d.children = null;
}
};
// Toggle children on click.
function click(d) {
if (d.children) {
d._children = d.children;
d.children = null;
} else {
d.children = d._children;
d._children = null;
}
update(d);
}
function update(source) {
// Compute the new tree layout.
var nodes = tree.nodes(root).reverse();
// Normalize for fixed-depth.
nodes.forEach(function(d) { d.y = d.depth * 180; });
// Update the nodes…
var node = vis.selectAll("g.node")
.data(nodes, function(d) { return d.id || (d.id = ++i); });
// Enter any new nodes at the parent's previous position.
var nodeEnter = node.enter().append("g")
.attr("class", "node")
.attr("transform", function(d) { return "translate(" + source.y0 + "," + source.x0 + ")"; })
.on("click", click);
nodeEnter.append("circle")
.attr("r", 1e-6)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; })
.on('mouseover', function(d, i){
var dataset = [1,2,3,4] // HERE
vis.selectAll("line") // HERE
.data(dataset) // HERE
.enter() // HERE
.append("line") // HERE
.attr("x1", this.x) // HERE'S THE PROBLEM FOR PERRY
.attr("y1", this.y) // HERE'S THE PROBLEM FOR PERRY
.attr("x2", 500) // HERE
.attr("y2", 500) // HERE
.style("stroke", "rgb(6,120,155)");} // HERE
);
nodeEnter.append("text")
.attr("x", function(d) { return d.children || d._children ? -10 : 10; })
.attr("dy", ".35em")
.attr("text-anchor", function(d) { return d.children || d._children ? "end" : "start"; })
.text(function(d) { return d.name; })
.style("fill-opacity", 1e-6);
// Transition nodes to their new position.
var nodeUpdate = node.transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + d.y + "," + d.x + ")"; });
nodeUpdate.select("circle")
.attr("r", 4.5)
.style("fill", function(d) { return d._children ? "lightsteelblue" : "#fff"; });
nodeUpdate.select("text")
.style("fill-opacity", 1);
// Transition exiting nodes to the parent's new position.
var nodeExit = node.exit().transition()
.duration(duration)
.attr("transform", function(d) { return "translate(" + source.y + "," + source.x + ")"; })
.remove();
nodeExit.select("circle")
.attr("r", 1e-6);
nodeExit.select("text")
.style("fill-opacity", 1e-6);
// Update the links…
var link = vis.selectAll("path.link")
.data(tree.links(nodes), function(d) { return d.target.id; });
// Enter any new links at the parent's previous position.
link.enter().insert("path", "g")
.attr("class", "link")
.attr("d", function(d) {
var o = {x: source.x0, y: source.y0};
return diagonal({source: o, target: o});
})
.transition()
.duration(duration)
.attr("d", diagonal);
// Transition links to their new position.
link.transition()
.duration(duration)
.attr("d", diagonal);
// Transition exiting nodes to the parent's new position.
link.exit().transition()
.duration(duration)
.attr("d", function(d) {
var o = {x: source.x, y: source.y};
return diagonal({source: o, target: o});
})
.remove();
// Stash the old positions for transition.
nodes.forEach(function(d) {
d.x0 = d.x;
d.y0 = d.y;
});
};
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6 réponses
la façon de déterminer les coordonnées dépend de l'élément avec lequel vous travaillez. Pour circle s par exemple, les attributs cx et cy déterminent la position centrale. En outre, vous pouvez avoir un translation appliqué par l'attribut transform qui change le point de référence de n'importe quelles coordonnées.
la plupart des moyens utilisés en général pour obtenir les coordonnées de l'écran ne fonctionneront pas pour les SVG. En outre, vous ne voulez pas absolue coordonnées si la ligne que vous voulez dessiner, c'est dans le même contenant que les éléments qu'il relie.
Edit:
dans votre code particulier, il est assez difficile d'obtenir la position du noeud car elle est déterminée par une traduction de l'élément parent. Vous devez donc obtenir l'attribut transform du noeud parent et en extraire la traduction.
d3.transform(d3.select(this.parentNode).attr("transform")).translate
Travail jsfiddle ici .
la méthode element.getBoundingClientRect() renverra les coordonnées appropriées d'un élément par rapport au viewport, que le svg ait été mis à l'échelle et/ou traduit.
voir cette question et réponse .
alors que getBBox() fonctionne pour un espace non transformé, si l'échelle et la traduction ont été appliquées à la disposition, alors elle ne sera plus précise. La fonction getBoundingClientRect() a cela a bien fonctionné pour moi dans un projet de mise en page de force quand pan et zoom sont en vigueur, où je voulais attacher des éléments HTML Div comme des étiquettes aux noeuds au lieu d'utiliser des éléments de texte SVG.
vous pouvez utiliser la fonction getBBox() pour obtenir la boîte de délimitation du chemin. Cela vous donnera la position et la taille du rectangle le plus étroit qui pourrait contenir le chemin Rendu.
l'avantage de cette méthode par rapport à la lecture des valeurs x et y est qu'elle fonctionne avec tous les objets graphiques. Il y a plus d'objets que de chemins qui n'ont pas x et y, par exemple des cercles qui ont cx et cy à la place.
j'utilise la fonction consolider, comme ainsi:
element.transform.baseVal.consolidate()
The .e et .les valeurs f correspondent aux coordonnées x et y
je peux gérer ça comme ça ;
svg.selectAll("rect")
.data(zones)
.enter()
.append("rect")
.attr("id", function (d) { return "zone" + d.zone; })
.attr("class", "zone")
.attr("x", function (d, i) {
if (parseInt(i / (wcount)) % 2 == 0) {
this.xcor = (i % wcount) * zoneW;
}
else {
this.xcor = (zoneW * (wcount - 1)) - ((i % wcount) * zoneW);
}
return this.xcor;
})
et plus vous pouvez trouver x coordonnée
svg.select("#zone1").on("click",function(){alert(this.xcor});
svg.selectAll("rect")
.attr('x',function(d,i){
// get x coord
console.log(this.getBBox().x, 'or', d3.select(this).attr('x'))
})
.attr('y',function(d,i){
// get y coord
console.log(this.getBBox().y)
})
.attr('dx',function(d,i){
// get dx coord
console.log(parseInt(d3.select(this).attr('dx')))
})