Formulaire soumettre avec AJAX transmettre des données de formulaire à PHP sans actualisation de la page

Question

Formulaire soumettre avec AJAX transmettre des données de formulaire à PHP sans actualisation de la page

Quelqu'un Peut me dire pourquoi ce code ne fonctionne pas?

<html>
  <head>
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <script>
      $(function () {
        $('form').bind('submit', function () {
          $.ajax({
            type: 'post',
            url: 'post.php',
            data: $('form').serialize(),
            success: function () {
              alert('form was submitted');
            }
          });
          return false;
        });
      });
    </script>
  </head>
  <body>
    <form>
      <input name="time" value="00:00:00.00"><br>
      <input name="date" value="0000-00-00"><br>
      <input name="submit" type="button" value="Submit">
    </form>
  </body>
</html>

Quand je pousse soumettre rien ne se passe. Dans le fichier php de réception, j'utilise $_POST['time'] et $_POST ['date'] pour placer les données dans une requête mysql, mais cela n'obtient tout simplement pas les données. Toutes les suggestions? Je suppose que c'est quelque chose à voir avec le bouton de soumission mais je ne peux pas le comprendre

47

ajax forms jquery php serialization

demandé sur Qix 2013-05-17 23:08:29

8 réponses

score 92 · Answer 1

Le formulaire est soumis après la demande ajax.

<html>
  <head>
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <script>
      $(function () {

        $('form').on('submit', function (e) {

          e.preventDefault();

          $.ajax({
            type: 'post',
            url: 'post.php',
            data: $('form').serialize(),
            success: function () {
              alert('form was submitted');
            }
          });

        });

      });
    </script>
  </head>
  <body>
    <form>
      <input name="time" value="00:00:00.00"><br>
      <input name="date" value="0000-00-00"><br>
      <input name="submit" type="submit" value="Submit">
    </form>
  </body>
</html>

score 12 · Answer 2

<html>
  <head>
    <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
    <script>
      $(function () {
        $('form').bind('click', function (event) {

event.preventDefault();// using this page stop being refreshing 

          $.ajax({
            type: 'POST',
            url: 'post.php',
            data: $('form').serialize(),
            success: function () {
              alert('form was submitted');
            }
          });

        });
      });
    </script>
  </head>
  <body>
    <form>
      <input name="time" value="00:00:00.00"><br>
      <input name="date" value="0000-00-00"><br>
      <input name="submit" type="submit" value="Submit">
    </form>
  </body>
</html>

PHP

<?php


$time="";
$date="";
if(isset($_POST['time'])){$time=$_POST['time']}
if(isset($_POST['date'])){$time=$_POST['date']}

echo $time."<br>";
echo $date;
?>

score 5 · Answer 3

Code JS

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/   libs/jquery/1.3.0/jquery.min.js">
</script>

<script type="text/javascript" >
  $(function() {
  $(".submit").click(function() {
  var time = $("#time").val();
  var date = $("#date").val();
  var dataString = 'time='+ time + '&date=' + date;

if(time=='' || date=='')
{
  $('.success').fadeOut(200).hide();
  $('.error').fadeOut(200).show();
}
else
{
  $.ajax({
    type: "POST",
    url: "post.php",
    data: dataString,
    success: function(){
     $('.success').fadeIn(200).show();
     $('.error').fadeOut(200).hide();
    }
  });
}
return false;
});
});
</script>

Formulaire HTML

   <form>
      <input id="time" value="00:00:00.00"><br>
      <input id="date" value="0000-00-00"><br>
      <input name="submit" type="button" value="Submit">
    </form>
<span class="error" style="display:none"> Please Enter Valid Data</span>
<span class="success" style="display:none"> Form Submitted Success</span>
</div>

Code PHP

<?php
if($_POST)
{
$date=$_POST['date'];
$time=$_POST['time'];
mysql_query("SQL insert statement.......");
}else { }

?>

Prises À Partir De Ici

score 4 · Answer 4

Voici un joli plugin pour jQuery qui soumet des formulaires via ajax:

Http://malsup.com/jquery/form/

C'est aussi simple que:

<script src="http://malsup.github.com/jquery.form.js"></script> 
<script> 
    $(document).ready(function() { 
        $('#myForm').ajaxForm(function() { 
           alert('form was submitted');
        }); 
    }); 
</script>

Il utilise l'action forms pour l'emplacement de poste. Non pas que vous ne pouvez pas y parvenir avec votre propre code, mais ce plugin a très bien fonctionné pour moi!

score 3 · Answer 5

Code JS

    $("#submit").click(function() { 
    //get input field values
    var name            = $('#name').val(); 
    var email           = $('#email').val();
    var message         = $('#comment').val();
    var flag = true;
    /********validate all our form fields***********/
    /* Name field validation  */
    if(name==""){ 
        $('#name').css('border-color','red'); 
        flag = false;
    }
    /* email field validation  */
    if(email==""){ 
        $('#email').css('border-color','red'); 
        flag = false;
    } 
    /* message field validation */
    if(message=="") {  
       $('#comment').css('border-color','red'); 
        flag = false;
    }
    /********Validation end here ****/
    /* If all are ok then we send ajax request to email_send.php *******/
    if(flag) 
    {
        $.ajax({
            type: 'post',
            url: "email_send.php", 
            dataType: 'json',
            data: 'username='+name+'&useremail='+email+'&message='+message,
            beforeSend: function() {
                $('#submit').attr('disabled', true);
                $('#submit').after('<span class="wait">&nbsp;<img src="image/loading.gif" alt="" /></span>');
            },
            complete: function() {
                $('#submit').attr('disabled', false);
                $('.wait').remove();
            },  
            success: function(data)
            {
                if(data.type == 'error')
                {
                    output = '<div class="error">'+data.text+'</div>';
                }else{
                    output = '<div class="success">'+data.text+'</div>';
                    $('input[type=text]').val(''); 
                    $('#contactform textarea').val(''); 
                }

                $("#result").hide().html(output).slideDown();           
                }
        });
    }
});
//reset previously set border colors and hide all message on .keyup()
$("#contactform input, #contactform textarea").keyup(function() { 
    $("#contactform input, #contactform textarea").css('border-color',''); 
    $("#result").slideUp();
});

Formulaire HTML

<div  class="cover">
<div id="result"></div>
<div id="contactform">
    <p class="contact"><label for="name">Name</label></p>
    <input id="name" name="name" placeholder="Yourname" type="text">

    <p class="contact"><label for="email">Email</label></p>
    <input id="email" name="email" placeholder="admin@admin.com" type="text">

    <p class="contact"><label for="comment">Your Message</label></p>
    <textarea name="comment" id="comment" tabindex="4"></textarea> <br>
    <input name="submit" id="submit" tabindex="5" value="Send Mail" type="submit" style="width:200px;">
</div>

Code PHP

if ($_SERVER['REQUEST_METHOD'] == 'POST') {

//check if its an ajax request, exit if not
if (!isset($_SERVER['HTTP_X_REQUESTED_WITH']) AND strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest') {

    //exit script outputting json data
    $output = json_encode(
            array(
                'type' => 'error',
                'text' => 'Request must come from Ajax'
    ));

    die($output);
}

//check $_POST vars are set, exit if any missing
if (!isset($_POST["username"]) || !isset($_POST["useremail"]) || !isset($_POST["message"])) {
    $output = json_encode(array('type' => 'error', 'text' => 'Input fields are empty!'));
    die($output);
}

//Sanitize input data using PHP filter_var().
$username = filter_var(trim($_POST["username"]), FILTER_SANITIZE_STRING);
$useremail = filter_var(trim($_POST["useremail"]), FILTER_SANITIZE_EMAIL);
$message = filter_var(trim($_POST["message"]), FILTER_SANITIZE_STRING);

//additional php validation
if (strlen($username) < 4) { // If length is less than 4 it will throw an HTTP error.
    $output = json_encode(array('type' => 'error', 'text' => 'Name is too short!'));
    die($output);
}
if (!filter_var($useremail, FILTER_VALIDATE_EMAIL)) { //email validation
    $output = json_encode(array('type' => 'error', 'text' => 'Please enter a valid email!'));
    die($output);
}
if (strlen($message) < 5) { //check emtpy message
    $output = json_encode(array('type' => 'error', 'text' => 'Too short message!'));
    die($output);
}

$to = "info@wearecoders.net"; //Replace with recipient email address
//proceed with PHP email.
$headers = 'From: ' . $useremail . '' . "\r\n" .
        'Reply-To: ' . $useremail . '' . "\r\n" .
        'X-Mailer: PHP/' . phpversion();

$sentMail = @mail($to, $subject, $message . '  -' . $username, $headers);
//$sentMail = true;
if (!$sentMail) {
    $output = json_encode(array('type' => 'error', 'text' => 'Could not send mail! Please contact administrator.'));
    die($output);
} else {
    $output = json_encode(array('type' => 'message', 'text' => 'Hi ' . $username . ' Thank you for your email'));
    die($output);
}

Cette page a un exemple plus simple http://wearecoders.net/submit-form-without-page-refresh-with-php-and-ajax/

score 2 · Answer 6

type="button"

Devrait être

type="submit"

2

répondu Amir 2013-05-17 19:22:19

score 0 · Answer 7

Dans la gestion des événements, passez l'objet de l'événement à la fonction, puis ajoutez une instruction, c'est-à-dire événement.preventDefault ();

Cela transmettra les données à la page Web sans les actualiser.

score 0 · Answer 8

$(document).ready(function(){
$('#userForm').on('submit', function(e){
        e.preventDefault();
//I had an issue that the forms were submitted in geometrical progression after the next submit. 
// This solved the problem.
        e.stopImmediatePropagation();
    // show that something is loading
    $('#response').html("<b>Loading data...</b>");

    // Call ajax for pass data to other place
    $.ajax({
    type: 'POST',
    url: 'somephpfile.php',
    data: $(this).serialize() // getting filed value in serialize form
    })
    .done(function(data){ // if getting done then call.

    // show the response
    $('#response').html(data);

    })
    .fail(function() { // if fail then getting message

    // just in case posting your form failed
    alert( "Posting failed." );

    });

    // to prevent refreshing the whole page page
    return false;

    });

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Formulaire soumettre avec AJAX transmettre des données de formulaire à PHP sans actualisation de la page

8 réponses