Le Client envoie la demande de SOAP et reçoit la réponse
essayer de créer un client C# (sera développé comme un service Windows) qui envoie des demandes SOAP à un service web (et obtient les résultats).
de ce question j'ai vu ce code:
protected virtual WebRequest CreateRequest(ISoapMessage soapMessage)
{
var wr = WebRequest.Create(soapMessage.Uri);
wr.ContentType = "text/xml;charset=utf-8";
wr.ContentLength = soapMessage.ContentXml.Length;
wr.Headers.Add("SOAPAction", soapMessage.SoapAction);
wr.Credentials = soapMessage.Credentials;
wr.Method = "POST";
wr.GetRequestStream().Write(Encoding.UTF8.GetBytes(soapMessage.ContentXml), 0, soapMessage.ContentXml.Length);
return wr;
}
public interface ISoapMessage
{
string Uri { get; }
string ContentXml { get; }
string SoapAction { get; }
ICredentials Credentials { get; }
}
a l'air sympa, quelqu'un sait comment l'utiliser et si c'est la meilleure pratique?
5 réponses
cependant, j'utilise normalement une autre façon de faire la même chose
using System.Xml;
using System.Net;
using System.IO;
public static void CallWebService()
{
var _url = "http://xxxxxxxxx/Service1.asmx";
var _action = "http://xxxxxxxx/Service1.asmx?op=HelloWorld";
XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
HttpWebRequest webRequest = CreateWebRequest(_url, _action);
InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);
// begin async call to web request.
IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);
// suspend this thread until call is complete. You might want to
// do something usefull here like update your UI.
asyncResult.AsyncWaitHandle.WaitOne();
// get the response from the completed web request.
string soapResult;
using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
{
using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
{
soapResult = rd.ReadToEnd();
}
Console.Write(soapResult);
}
}
private static HttpWebRequest CreateWebRequest(string url, string action)
{
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
webRequest.Headers.Add("SOAPAction", action);
webRequest.ContentType = "text/xml;charset=\"utf-8\"";
webRequest.Accept = "text/xml";
webRequest.Method = "POST";
return webRequest;
}
private static XmlDocument CreateSoapEnvelope()
{
XmlDocument soapEnvelopeDocument = new XmlDocument();
soapEnvelopeDocument.LoadXml(@"<SOAP-ENV:Envelope xmlns:SOAP-ENV=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:xsi=""http://www.w3.org/1999/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/1999/XMLSchema""><SOAP-ENV:Body><HelloWorld xmlns=""http://tempuri.org/"" SOAP-ENV:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/""><int1 xsi:type=""xsd:integer"">12</int1><int2 xsi:type=""xsd:integer"">32</int2></HelloWorld></SOAP-ENV:Body></SOAP-ENV:Envelope>");
return soapEnvelopeDocument;
}
private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
using (Stream stream = webRequest.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
}
j'ai eu cette solution simple ici :
envoyer la demande SOAP et recevoir la réponse dans .NET 4.0 C# sans utiliser les classes WSDL ou proxy:
class Program
{
/// <summary>
/// Execute a Soap WebService call
/// </summary>
public static void Execute()
{
HttpWebRequest request = CreateWebRequest();
XmlDocument soapEnvelopeXml = new XmlDocument();
soapEnvelopeXml.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<HelloWorld xmlns=""http://tempuri.org/"" />
</soap:Body>
</soap:Envelope>");
using (Stream stream = request.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
using (WebResponse response = request.GetResponse())
{
using (StreamReader rd = new StreamReader(response.GetResponseStream()))
{
string soapResult = rd.ReadToEnd();
Console.WriteLine(soapResult);
}
}
}
/// <summary>
/// Create a soap webrequest to [Url]
/// </summary>
/// <returns></returns>
public static HttpWebRequest CreateWebRequest()
{
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(@"http://localhost:56405/WebService1.asmx?op=HelloWorld");
webRequest.Headers.Add(@"SOAP:Action");
webRequest.ContentType = "text/xml;charset=\"utf-8\"";
webRequest.Accept = "text/xml";
webRequest.Method = "POST";
return webRequest;
}
static void Main(string[] args)
{
Execute();
}
}
la meilleure pratique est de faire référence à la WSDL et de l'utiliser comme une référence de service web. Plus facile et fonctionne bien, mais si vous n'avez pas les définitions WSDL ou XSD est un bon pice de code.
je pense qu'il y a un moyen plus simple:
public async Task<string> CreateSoapEnvelop()
{
string soapString = @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<HelloWorld xmlns=""http://tempuri.org/"" />
</soap:Body>
</soap:Envelope>";
HttpResponseMessage response = await PostXmlRequest("your_url_here", soapString);
string content = await response.Content.ReadAsStringAsync();
return content;
}
public static async Task<HttpResponseMessage> PostXmlRequest(string baseUrl, string xmlString)
{
using (var httpClient = new HttpClient())
{
var httpContent = new StringContent(xmlString, Encoding.UTF8, "text/xml");
httpContent.Headers.Add("SOAPAction", "http://tempuri.org/HelloWorld");
return await httpClient.PostAsync(baseUrl, httpContent);
}
}
j'ai écrit une classe d'aide plus générale qui accepte un dictionnaire de paramètres personnalisés basé sur les chaînes de caractères, de sorte qu'ils puissent être définis par l'appelant sans avoir à les coder. Il va sans dire que vous ne devez utiliser cette méthode que lorsque vous voulez (ou avez besoin) de lancer manuellement un service Web SOAP: dans la plupart des scénarios courants, l'approche recommandée serait d'utiliser le service Web WSDL avec le ajouter référence de Service fonction Visual Studio à la place.
using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Net;
using System.Xml;
namespace Ryadel.Web.SOAP
{
/// <summary>
/// Helper class to send custom SOAP requests.
/// </summary>
public static class SOAPHelper
{
/// <summary>
/// Sends a custom sync SOAP request to given URL and receive a request
/// </summary>
/// <param name="url">The WebService endpoint URL</param>
/// <param name="action">The WebService action name</param>
/// <param name="parameters">A dictionary containing the parameters in a key-value fashion</param>
/// <param name="soapAction">The SOAPAction value, as specified in the Web Service's WSDL (or NULL to use the url parameter)</param>
/// <param name="useSOAP12">Set this to TRUE to use the SOAP v1.2 protocol, FALSE to use the SOAP v1.1 (default)</param>
/// <returns>A string containing the raw Web Service response</returns>
public static string SendSOAPRequest(string url, string action, Dictionary<string, string> parameters, string soapAction = null, bool useSOAP12 = false)
{
// Create the SOAP envelope
XmlDocument soapEnvelopeXml = new XmlDocument();
var xmlStr = (useSOAP12)
? @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap12:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
xmlns:xsd=""http://www.w3.org/2001/XMLSchema""
xmlns:soap12=""http://www.w3.org/2003/05/soap-envelope"">
<soap12:Body>
<{0} xmlns=""{1}"">{2}</{0}>
</soap12:Body>
</soap12:Envelope>"
: @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/""
xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance""
xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
<soap:Body>
<{0} xmlns=""{1}"">{2}</{0}>
</soap:Body>
</soap:Envelope>";
string parms = string.Join(string.Empty, parameters.Select(kv => String.Format("<{0}>{1}</{0}>", kv.Key, kv.Value)).ToArray());
var s = String.Format(xmlStr, action, new Uri(url).GetLeftPart(UriPartial.Authority) + "/", parms);
soapEnvelopeXml.LoadXml(s);
// Create the web request
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
webRequest.Headers.Add("SOAPAction", soapAction ?? url);
webRequest.ContentType = (useSOAP12) ? "application/soap+xml;charset=\"utf-8\"" : "text/xml;charset=\"utf-8\"";
webRequest.Accept = (useSOAP12) ? "application/soap+xml" : "text/xml";
webRequest.Method = "POST";
// Insert SOAP envelope
using (Stream stream = webRequest.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
// Send request and retrieve result
string result;
using (WebResponse response = webRequest.GetResponse())
{
using (StreamReader rd = new StreamReader(response.GetResponseStream()))
{
result = rd.ReadToEnd();
}
}
return result;
}
}
}
pour des informations supplémentaires et des détails concernant cette classe, vous pouvez aussi lire ce message .